Advertisements
Advertisements
प्रश्न
If 0° < A < 90°; find A, if `(cos A )/(1 - sin A) + (cos A)/(1 + sin A) = 4`
Advertisements
उत्तर
`(cos A )/(1 - sin A) + (cos A)/(1 + sin A) = 4`
`=> (cos A + cos A sin A + cos A - sin A cos A)/((1 - sin A)(1 + sin A)) = 4`
`=> (2 cos A)/(1 - sin^2 A) = 4`
`=> (2 cos A)/(cos^2 A) = 4`
`=> 1/cos A = 2`
`=> cos A = 1/2`
We know `cos 60^circ = 1/2`
Hence, A = 60°
APPEARS IN
संबंधित प्रश्न
If tan A = cot B, prove that A + B = 90°.
If `cosec A = sqrt2` find the value of `(2 sin^2 A + 3 cot^2 A)/(4(tan^2 A - cos^2 A))`
Evaluate.
cos225° + cos265° - tan245°
Evaluate:
3cos80° cosec10° + 2 sin59° sec31°
Find the value of angle A, where 0° ≤ A ≤ 90°.
cos (90° – A) . sec 77° = 1
Use tables to find the acute angle θ, if the value of tan θ is 0.2419
Evaluate:
`(3sin72^@)/(cos18^@) - sec32^@/(cosec58^@)`
Find A, if 0° ≤ A ≤ 90° and 2 cos2 A – 1 = 0
If A and B are complementary angles, then
If x tan 45° cos 60° = sin 60° cot 60°, then x is equal to
