Advertisements
Advertisements
प्रश्न
Evaluate : `[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`
बेरीज
Advertisements
उत्तर
`[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`
= `[(- 3/2 )^2]^3 xx (3)^4 xx 1/3 xx 1/[ 3 xx 2 ]`
= `( -3/2)^6 xx (3)^2 xx 1/2`
= `3^(6 + 2 )/2^(6 + 1)`
= `3^8/2^7`
shaalaa.com
Solving Exponential Equations
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Solve : `[3^x]^2` : 3x = 9 : 1
Evaluate the following:
`(2^6 xx 5^-4 xx 3^-3 xx 4^2)/(8^3 xx 15^-3 xx 25^-1)`
Solve for x:
`9 xx 3^x = (27)^(2x - 5)`
Solve for x:
1 = px
Solve for x:
22x- 1 − 9 x 2x − 2 + 1 = 0
If x = `3^(2/3) + 3^(1/3)`, prove that x3 - 9x - 12 = 0
If ax = by = cz and b2 = ac, prove that y = `(2xz)/(z + x)`
Show that : `(1)/(1 + "a"^("p"- "q")) + (1)/(1 + "a"^("q"- "p")`
Find the value of (8p)p if 9p + 2 - 9p = 240.
Prove the following:
`root("ab")(x^"a"/x^"b")·root("bc")(x^"b"/x^"c")·root("ca")(x^"c"/x^"a")` = 1
