Advertisements
Advertisements
प्रश्न
Evaluate the following:
`(8/27)^((-2)/3) - (1/3)^-2 - 7^0`
Advertisements
उत्तर
`(8/27)^((-2)/3) - (1/3)^-2 - 7^0`
= `(27/8)^(2/3) - (3)^2 - 1`
= `(3/2)^(3 xx 2/3) - 9 - 1`
= `(3/2)^2 - 10`
= `(9)/(4) - 10`
= `(9 - 40)/(4)`
= `(-31)/(4)`.
APPEARS IN
संबंधित प्रश्न
Solve : 4x - 2 - 2x + 1 = 0
Solve for x: `4^(x-1) × (0.5)^(3 - 2x) = (1/8)^-x`
Solve for x:
`(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`
If `((a^-1b^2 )/(a^2b^-4))^7 ÷ (( a^3b^-5)/(a^-2b^3))^-5 = a^x . b^y` , find x + y.
Evaluate the following:
`(12^2 xx 75^-2 xx 35 xx 400)/(48^2 xx 15^-3 xx 525)`
Evaluate the following:
`(1 - 15/64)^(-1/2)`
Solve for x:
22x + 2x +2 - 4 x 23 = 0
Solve for x:
5x2 : 5x = 25 : 1
Find the value of k in each of the following:
`(root(3)(8))^((-1)/(2)` = 2k
Show that : `(1)/(1 + "a"^("p"- "q")) + (1)/(1 + "a"^("q"- "p")`
