मराठी

Equation of the circle with centre on the y-axis and passing through the origin and the point (2, 3) is ______.

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प्रश्न

Equation of the circle with centre on the y-axis and passing through the origin and the point (2, 3) is ______.

पर्याय

  • x2 + y2 + 13y = 0

  • 3x2 + 3y2 + 13x + 3 = 0

  • 6x2 + 6y2 – 13x = 0

  • x2 + y2 + 13x + 3 = 0

MCQ
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उत्तर

Equation of the circle with centre on the y-axis and passing through the origin and the point (2, 3) is x2 + y2 + 13y = 0.

Explanation:

Let the equation of the circle be (x – h)2 + (y – k)2 = r2

Let the centre be (0, a)

∴ Radius r = a

So, the equation of the circle is (x – 0)2 + (y – a)2 = a2

⇒ x2 + (y – a)2 = a2

⇒ x2 + y2 + a2 – 2ay = a2

⇒ x2 + y2 – 2ay = 0   ......(i)

Now CP = r

⇒ `sqrt((2 - 0)^2 + (3 - a)^2) = a`

⇒ `sqrt(4 + 9 + a^2 - 6a) = a`

⇒ `sqrt(13 + a^2 - 6a) = a`

⇒ `13 + a^2 - 6a = a^2`

⇒ `13 - 6a = 0`

∴ `a = 13/6`

Putting the value of a in equation (i) we get

`x^2 + y^2 - 2(13/6)y` = 0

⇒ 3x2 + 3y2 – 13y = 0

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Advanced Concept of Circle - Standard Equation of a Circle
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पाठ 11: Conic Sections - Exercise [पृष्ठ २०५]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 11 Conic Sections
Exercise | Q 49 | पृष्ठ २०५

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