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प्रश्न
Draw a labelled diagram of a moving coil galvanometer. Describe briefly its principle and working.
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उत्तर
Principle:
Its working is based on the fact that when a current carrying coil is placed in a magnetic field, it experiences a torque.

Working:
Suppose the coil PQRS is suspended freely in the magnetic field.
Let l = length PQ or RS of the coil
b = breadth QR or SP of the coil
n = number of turns in the coil
Area of each turn of the coil, A = l × b
Let B = strength of the magnetic field in which the coil is suspended
I = current passing through the coil in the direction PQRS
At any instant, let α be the angle that the normal drawn on the plane of the coil makes with the direction of magnetic field.
The rectangular coil carrying current, when placed in the magnetic field, experiences a torque whose magnitude is given by:
τ = nIBA sinα
Due to the deflecting torque, the coil rotates and the suspension wire gets twisted. A restoring torque is set up in the suspension wire.
Let θ be the twist produced in the phosphor bronze strip due to the rotation of the coil and K be the restoring torque per unit twist of the phosphor bronze strip. Then, we have:
Total restoring torque produced = kθ
In equilibrium position of the coil, we have:
Deflecting torque = Restoring torque
∴ NIBA = kθ
or
`I=k/(NBA)theta " or "Gtheta`
Here,
`K/(NBA)=G=a["constant for a galvanometer"]`
It is known as galvanometer constant.
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संबंधित प्रश्न
A rectangular coil of a moving coil galvanometer contains 50 turns each having area 12 cm2 . It is suspended in radial magnetic field 0.025 Wb/m2 by a fibre of twist constant 15 x10-10 Nm/degree. Calculate the sensitivity of the moving coil galvanometer.
Why does a galvanometer show a momentary deflection at the time of charging or discharging a capacitor? Write the necessary expression to explain this observation.
Why is it necessary to introduce a cylindrical soft iron core inside the coil of a galvanometer?
Two moving coil meters, M1 and M2 have the following particulars:
R1 = 10 Ω, N1 = 30,
A1 = 3.6 × 10–3 m2, B1 = 0.25 T
R2 = 14 Ω, N2 = 42,
A2 = 1.8 × 10–3 m2, B2 = 0.50 T
(The spring constants are identical for the two meters.)
Determine the ratio of
- current sensitivity and
- voltage sensitivity of M2 and M1.
The fraction of the total current passing through the galvanometer is ............ .
a) `S/(S+G)`
b) `G/(S+G)`
c) `(S+G)/G`
d) `(S+G)/S`
How will you convert a moving coil galvanometer into a voltmeter?
What are the advantages of using soft iron as a core, instead of steel, in the coils of galvanometers?
Assertion (A): On Increasing the current sensitivity of a galvanometer by increasing the number of turns may not necessarily increase its voltage sensitivity.
Reason (R): The resistance of the coil of the galvanometer increases on increasing the number of turns.
Select the most appropriate answer from the options given below:
In an ammeter 0.5% of main current passes through galvanometer; If resistance of galvanometer is G, the resistance of ammeter will be.
A resistance of 3Ω is connected in parallel to a galvanometer of resistance 297Ω. Find the fraction of current passing through the galvanometer.
