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प्रश्न
Differentiate between an efflorescent, deliquescent & ‘ hygroscopic substance with suitable examples.
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उत्तर
- Lose wholly or partially their water of crystallisation when exposed to air.
- Become powdery.
- Washing soda CaCO3.10H2O, Gauber’s salt
Na2SO4.10H2O, epsom salt MgSO4.7H2O
\[\ce{Na2CO.10H2O->[dry air]Na2CO3.H2O + 9H2O}\]
- Crystalline when hydrated.
Deliquescent substances:
- Absorb moisture from atmosphere, absorb water and dissolve in it forming a saturated solution.
- Deliquescence is maximized in dry conditions,
- NaOH, KOH, CaCl2, MgCl2, FeCl3 are the examples.
- They are crystalline water soluble.
FeCl3 → FeCl3 [Crystal changes to Solution]
Hygroscopic substances:
- They are amorphous solids or liquids.
- Absorb moisture from the air of atmosphere.
- Do not change their original state.
CaO (quick lime), cone. H2SO4, P2O5 and silica gel are the examples.
\[\ce{\underset{\text{Conc.}}{H2SO4} ->\underset{\text{Conc.}}{H2SO4}}\]
(State not changed)
is used for drying gases in laboratory.
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संबंधित प्रश्न
The sticky substance formed when soap is added to hard water is ______.
Give the names and formulae of two substances.
Hydrated substance
What are drying or desiccating agents? Give examples.
Differentiate the function of concentrated sulphuric acid as a drying agent & as a dehydrating agent. Is fused calcium chloride a dehydrating or a desiccating agent. Give reasons.
Explain the following observation:
In the expression anhydrous copper sulphate, what is meant by “anhydrous”?
Select the correct word from the words in option to complete the sentence:
Efflorescence occurs when the vapour pressure of the hydrated crystals is ____ than the vapour pressure of the atmospheric humidity.
Select the correct answer from the choice given in the options.
An anhydrous crystal _____.
Match the following
| 1. | Blue vitriol | CaSO4.2H2O |
| 2. | Gypsum | CaO |
| 3. | Deliquescence | CuSO4.5H2O |
| 4. | Hygroscopic | NaOH |
The molecular formula of green vitriol is MgSO4.7H2O.
'A' is a blue coloured crystalline salt. On heating, it loses blue colour and to give 'B'. When water is added, 'B' gives back to 'A'. Identify A and B, write the equation.
