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प्रश्न
'A' is a blue coloured crystalline salt. On heating, it loses blue colour and to give 'B'. When water is added, 'B' gives back to 'A'. Identify A and B, write the equation.
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उत्तर
Since ‘A’ is a blue coloured crystalline salt, it is CuSO4. 5H2O (Blue vitriol). On heating, it loses all five water molecules and becomes colourless anhydrous CuSO4.
\[\ce{\underset{\text{(A)}}{CuSO4.5H2O} ⇌[heating][cooling]\underset{\text{anhy. copper sulphate} Colourless (B)}{CuSO4 + 5H2O}}\]
When water is added ‘B’ gives back A.
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संबंधित प्रश्न
Define water of crystallization. Give two examples with formulae.
What do you observe when Blue vitriol is heated?
Water turns the colour of anhydrous copper sulphate .................
Give one word for the following statement:
A substance which does not contain water .
The substance that can remove hydrogen and oxygen atoms in the ratio of 2:1(in the form of water) from the compound.
State the methods by which hydrated salts can be made anhydrous.
The process of separation or deposition of crystals from a hot saturated solution on gentle cooling of the solution is called ‘crystallization’. With reference to the statement explain what is meant by ‘water of crystallization. State which physical properties of a crystal are correlated with the water of crystallization.
Select the correct word from the words in option to complete the sentence:
Efflorescence occurs when the vapour pressure of the hydrated crystals is ____ than the vapour pressure of the atmospheric humidity.
A hot saturated solution of copper sulphate forms crystals as it cools. Why?
What happens when MgSO4.7H2O is heated? Write the appropriate equation?
