Advertisements
Advertisements
प्रश्न
\[\frac{dy}{dx} = x^2 e^x\]
Advertisements
उत्तर
We have,
\[\frac{dy}{dx} = x^2 e^x \]
\[ \Rightarrow dy = x^2 e^x dx\]
Integrating both sides, we get

\[ \Rightarrow \int dy = x^2 \int e^x dx - \int\left( \frac{d}{dx}\left( x^2 \right)\int e^x dx \right)dx\]
\[ \Rightarrow y = x^2 e^x - 2\int x e^x dx\]

\[ \Rightarrow y = x^2 e^x - 2x\int e^x dx + 2\int\left( \frac{d}{dx}\left( x \right)\int e^x dx \right)dx\]
\[ \Rightarrow y = x^2 e^x - 2x e^x + 2 e^x + C\]
\[ \Rightarrow y = \left( x^2 - 2x + 2 \right) e^x + C\]
APPEARS IN
संबंधित प्रश्न
Find the differential equation representing the family of curves v=A/r+ B, where A and B are arbitrary constants.
Form a differential equation representing the given family of curves by eliminating arbitrary constants a and b.
`x/a + y/b = 1`
Form a differential equation representing the given family of curves by eliminating arbitrary constants a and b.
y = a e3x + b e– 2x
Find the particular solution of the differential equation (1 + e2x) dy + (1 + y2) ex dx = 0, given that y = 1 when x = 0.
Solve the differential equation `ye^(x/y) dx = (xe^(x/y) + y^2)dy, (y != 0)`
Find a particular solution of the differential equation (x - y) (dx + dy) = dx - dy, given that y = -1, when x = 0. (Hint: put x - y = t)
The general solution of the differential equation `(y dx - x dy)/y = 0` is ______.
Find the differential equation representing the family of curves `y = ae^(bx + 5)`. where a and b are arbitrary constants.
Find the differential equation of all the circles which pass through the origin and whose centres lie on y-axis.
Find the differential equation of all the circles which pass through the origin and whose centres lie on x-axis.
Verify that y = A cos x + sin x satisfies the differential equation \[\cos x\frac{dy}{dx} + \left( \sin x \right)y=1.\]
Find the differential equation corresponding to y = ae2x + be−3x + cex where a, b, c are arbitrary constants.
\[\frac{dy}{dx} = \sin^3 x \cos^4 x + x\sqrt{x + 1}\]
\[\frac{dy}{dx} = \frac{1}{x^2 + 4x + 5}\]
\[\frac{dy}{dx} + 4x = e^x\]
\[\frac{dy}{dx} - x \sin^2 x = \frac{1}{x \log x}\]
\[(\tan^2 x + 2\tan x + 5)\frac{dy}{dx} = 2(1+\tan x)\sec^2x\]
\[\frac{dy}{dx} = \sin^3 x \cos^2 x + x e^x\]
tan y dx + tan x dy = 0
(1 + x) y dx + (1 + y) x dy = 0
cos y log (sec x + tan x) dx = cos x log (sec y + tan y) dy
cosec x (log y) dy + x2y dx = 0
Find the general solution of the differential equation `"dy"/"dx" = y/x`.
Solve the differential equation:
cosec3 x dy − cosec y dx = 0
General solution of tan 5θ = cot 2θ is
The number of arbitrary constant in the general solution of a differential equation of fourth order are
Which of the following equations has `y = c_1e^x + c_2e^-x` as the general solution?
The general solution of the differential equation `(dy)/(dx) = e^(x + y)` is
What is the general solution of differential equation `(dy)/(dx) = sqrt(4 - y^2) (-2 < y < 2)`
The general solution of the differential equation y dx – x dy = 0 is ______.
