Advertisements
Advertisements
प्रश्न
Construct a parallelogram ABCD in which AB = 4 cm, BC = 5 cm and ∠B = 60°.
Advertisements
उत्तर
As we know that the opposite sides of a parallelogram are equal.
So, AB = DC = 4 cm
BC = AD = 5 cm
∠B = 60°
∠A + ∠B = 180° ...[Sum of cointerior angles]
∠A = 180°
Steps of construction:
Step I: Draw AB = 4 cm.
Step II: Draw ray BX that is ∠ABX = 60°.
Step III: Mark a point C that is BC = 5 cm.
Step IV: Draw a ray AY that is ∠YAB = 120.
Step V: Mark a point D that is AD = 5 cm.
Step VI: Join C and D.
Hence, ABCD is required parallelogram.
APPEARS IN
संबंधित प्रश्न
Consider the given parallelograms. Find the values of the unknowns x, y, z.

Can a quadrilateral ABCD be a parallelogram if ∠A = 70° and ∠C = 65°?
In the given figure, `square`PQRS and `square`ABCR are two parallelograms. If ∠P = 110° then find the measures of all angles of `square`ABCR.

In the given figure, G is the point of concurrence of medians of ΔDEF. Take point H on ray DG such that D-G-H and DG = GH, then prove that `square`GEHF is a parallelogram.

In parallelogram ABCD, ∠A = 3 times ∠B. Find all the angles of the parallelogram. In the same parallelogram, if AB = 5x – 7 and CD = 3x +1 ; find the length of CD.
In parallelogram ABCD, E is the mid-point of AD and F is the mid-point of BC. Prove that BFDE is a parallelogram.
In parallelogram ABCD, X and Y are midpoints of opposite sides AB and DC respectively. Prove that:
(i) AX = YC
(ii) AX is parallel to YC
(iii) AXCY is a parallelogram.
In parallelogram LOST, SN ⊥ OL and SM ⊥ LT. Find ∠STM, ∠SON and ∠NSM.

ABCD is a parallelogram. The bisector of angle A intersects CD at X and bisector of angle C intersects AB at Y. Is AXCY a parallelogram? Give reason.
In the following figure, FD || BC || AE and AC || ED. Find the value of x.

