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प्रश्न
Construct a trapezium ABCD in which AB || DC, ∠A = 105°, AD = 3 cm, AB = 4 cm and CD = 8 cm.
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उत्तर
We know that,

∠A + ∠D = 180° ...[Sum of adjacent angle of a trapezium is 180°]
105° + ∠D = 180°
∠D = 180° – 105°
∠D = 75°
Steps of construction:
Step I: Draw AB = 4 cm.
Step II: Draw `bar(AX)` that is ∠BAX = 105°.
Step III: Mark a point D on AX that is AD = 3 cm.
Step IV: Draw `bar(DY)` that is ∠ADY = 75°.
Step V: Mark a point C that is CD = 8 cm.
Step VI: Join BC.
Hence, ABCD is the required trapezium.
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[Hint: Difference of two parallel sides gives an equilateral triangle.]
