Advertisements
Advertisements
प्रश्न
Find the value of x in the trapezium ABCD given below.
Advertisements
उत्तर
Given, A trapezium ABCD in which ∠A = (x – 20)°, ∠D = (x + 40)°
Since, In a trapezium, the angle on either side of the base are supplementary,
Therefore, (x – 20)° + (x + 40)° = 180°
⇒ x – 20° + x + 40° = 180°
⇒ 2x + 20° = 180°
⇒ 2x = (180° – 20°)
⇒ 2x = 160°
⇒ x = 80°
APPEARS IN
संबंधित प्रश्न
Find m∠C in the following figure if `bar(AB) || bar(DC)`
All squares are trapeziums.
In `square`ABCD, side BC || side AD, side AB ≅ side DC If ∠A = 72° then find the measure of ∠B and ∠D.
In `square`ABCD, side BC < side AD in following figure. side BC || side AD and if side BA ≅ side CD then prove that ∠ABC ≅ ∠DCB.
In the given figure CE || DB then the value of x° is
In trapezium ABCD with AB || CD, if ∠A = 100°, then ∠D = ______.
All angles of a trapezium are equal.
In trapezium HARE, EP and RP are bisectors of ∠E and ∠R respectively. Find ∠HAR and ∠EHA.
ABCD is a trapezium such that AB || CD, ∠A : ∠D = 2 : 1, ∠B : ∠C = 7 : 5. Find the angles of the trapezium.
Construct a trapezium ABCD where AB || CD, AD = BC = 3.2 cm, AB = 6.4 cm and CD = 9.6 cm. Measure ∠B and ∠A.
[Hint: Difference of two parallel sides gives an equilateral triangle.]
