Advertisements
Advertisements
प्रश्न
In trapezium HARE, EP and RP are bisectors of ∠E and ∠R respectively. Find ∠HAR and ∠EHA.

Advertisements
उत्तर
As EP and PR are angle bisectors of ∠REH and ∠ARE respectively. ...[Given]
Since, HARE is a trapezium,
Therefore, ∠E + ∠H = 180° and ∠R + ∠A = 180°
⇒ ∠PER + ∠PEH + ∠H = 180° and ∠ERP + ∠PRA + ∠RAH = 180°
⇒ 25° + 25° + ∠H = 180° and 30° + 30° + ∠A = 180°
⇒ 50° + ∠H = 180° and 60° + ∠A = 180°
⇒ ∠H = 130° and ∠A = 120°, i.e. ∠EHA = 130° and ∠HAR = 120°
APPEARS IN
संबंधित प्रश्न
Explain how this figure is a trapezium. Which of its two sides are parallel?

Find m∠C in the following figure if `bar(AB) || bar(DC)`

In `square`ABCD, side BC || side AD, side AB ≅ side DC If ∠A = 72° then find the measure of ∠B and ∠D.
A quadrilateral in which a pair of opposite sides is parallel is ______.
In trapezium ABCD with AB || CD, if ∠A = 100°, then ∠D = ______.
Every trapezium is a parallelogram.
Every rhombus is a trapezium.
Find the value of x in the trapezium ABCD given below.

In a quadrilateral HOPE, PS and ES are bisectors of ∠P and ∠E respectively. Give reason.
Construct a trapezium ABCD where AB || CD, AD = BC = 3.2 cm, AB = 6.4 cm and CD = 9.6 cm. Measure ∠B and ∠A.

[Hint: Difference of two parallel sides gives an equilateral triangle.]
