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प्रश्न
Find the value of x in the trapezium ABCD given below.
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उत्तर
Given, A trapezium ABCD in which ∠A = (x – 20)°, ∠D = (x + 40)°
Since, In a trapezium, the angle on either side of the base are supplementary,
Therefore, (x – 20)° + (x + 40)° = 180°
⇒ x – 20° + x + 40° = 180°
⇒ 2x + 20° = 180°
⇒ 2x = (180° – 20°)
⇒ 2x = 160°
⇒ x = 80°
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