मराठी

Calculate the velocity of a body of mass 0.5 kg, when it has a linear momentum of 5 Ns. - Physics

Advertisements
Advertisements

प्रश्न

Calculate the velocity of a body of mass 0.5 kg, when it has a linear momentum of 5 Ns.

संख्यात्मक
Advertisements

उत्तर

Mass of body = m = 0.5 kg
Linear momentum = P = 5 Ns
Velocity of body = v = ?
We know P = mv
v = `"P"/"m"=5/0.5`
v = 10 ms−1

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Laws of Motion - Unit I Practice Problems 1

संबंधित प्रश्‍न

A spy jumps from an airplane with his parachute. The spy accelerates downward for some time when the parachute opens. The acceleration is suddenly checked and the spy slowly falls to the ground. Explain the action of the parachute in checking the acceleration.


In a TV picture tube, electrons are ejected from the cathode with negligible speed and they attain a velocity of 5 × 106 m/s in travelling one centimetre. Assuming straight-line motion, find the constant force exerted on the electrons. The mass of an electron is 9.1 × 10−31 kg.


A small block B is placed on another block A of mass 5 kg and length 20 cm. Initially, the block B is near the right end of block A (In the following Figure). A constant horizontal force of 10 N is applied to the block A. All the surfaces are assumed frictionless. Find the time that elapses before block B separates from A.


Two balls A and B of masses m and 2 m are in motion with velocities 2v and v, respectively. Compare:

(i) Their inertia.

(ii) Their momentum.

(iii)  The force needed to stop them in the same time.


Write the mathematical form of Newton's second law of motion. State the conditions if any.


A force of 10 N acts on a body of mass 2 kg for 3 s, initially at rest. Calculate : Change in momentum of the body.


A stone is dropped freely from the top of a tower and it reaches the ground in 4 s. Taking g = 10m s-2, calculate the height of the tower.


State two factors which determine the momentum of a body.


Use Newton's second law to explain the following:
We always prefer to land on sand instead of hard floor while taking a high jump.


The motion of a particle of mass m is given by x = 0 for t < 0 s, x(t) = A sin 4 pt for 0 < t < (1/4) s (A > o), and x = 0 for t > (1/4) s. Which of the following statements is true?

  1. The force at t = (1/8) s on the particle is – 16π2 Am.
  2. The particle is acted upon by on impulse of magnitude 4π2 A m at t = 0 s and t = (1/4) s.
  3. The particle is not acted upon by any force.
  4. The particle is not acted upon by a constant force.
  5. There is no impulse acting on the particle.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×