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Balance the following ionic equations. MnOX4−+SOX32−+HX+⟶MnX2++SOX42−+HX2O

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प्रश्न

Balance the following ionic equations.

\[\ce{MnO^{-}4 + SO^{2-}3 + H^{+} -> Mn^{2+} + SO^{2-}4 + H2O}\]

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उत्तर


Dividing the equation into two half-reactions:

Oxidation half-reaction: \[\ce{SO^{2-}3 -> SO^{2-}4}\]

Reduction half-reaction: \[\ce{MnO^{-}4 -> MN^{2+}}\]

Balancing oxidation and reduction half-reactions separately as:

Oxidation half-reaction:

\[\ce{SO^{2-}3 -> SO^{2-}4}\]

\[\ce{SO^{2-}3 -> SO^{2-}4 + 2e-}\]

Since the reaction occurs in acidic medium,

\[\ce{SO^{2-}3 -> SO^{2-}4 + 2e^{-} + 2H+}\]

\[\ce{SO^{2-}3  + H2O -> SO^{2-}4 + 2H^{+} + 2e-}\]  .....(i)

Reduction half-reaction:

\[\ce{MnO^{-}4 -> MN^{2+}}\]

\[\ce{MnO^{-}4  + 5e^{-} -> MN^{2+}}\]

\[\ce{MnO^{-}4  + 5e^{-} -> MN^{2+} + 4H2O}\]  .....(ii)

To balance the electrons, multiply equation (i) by 5 and equation (ii) by 2 and add

\[\ce{2MO^{-}4 + 5SO^{2-}3 + 6H+ -> 2Mn^{2+} + 5SO^{2-}4 + 3H2O}\]

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पाठ 8: Redox Reactions - Multiple Choice Questions (Type - I) [पृष्ठ १०८]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
पाठ 8 Redox Reactions
Multiple Choice Questions (Type - I) | Q 26.(iii) | पृष्ठ १०८

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