Advertisements
Advertisements
प्रश्न
At what distance from a concave mirror of focal length 25 cm should an object be placed so that the size of image is equal to the size of the object.
Advertisements
उत्तर
If an object is placed at the centre of curvature of a concave mirror, the size of the image is equal to the size of the object.
Given,
focal length = 25 cm
As, center of curvature = 2 × focal length
Therefore,
center of curvature
= 2 × 25
= 50 cm
Hence, the object should be placed at 50 cm.
APPEARS IN
संबंधित प्रश्न
What is a virtual image?
A diverging lens is used in:
(a) a magnifying glass
(b) a car to see objects on rear side
(c) spectacles for the correction of short sight
(d) a simple camera
A small object is placed 150 mm away from a diverging lens of focal length 100 mm.
(i) Copy the figure below and draw rays to show how an image is formed by the lens.
Figure
(ii) Calculate the distance of the image from the lens by using the lens formula.
Complete the following diagrams in Figure by drawing the reflected rays for the incident rays 1 and 2.
The erect image formed by a concave mirror is of size double the size of object. How are u and v related?
The boxes in figure (a, b, c) represent mirrors; insert a mirror which will reflect the incident ray as shown in the diagram.
Complete the following diagrams shown in the following figures by drawing the reflected rays.
Define the term Normal.
The spherical mirror used in a beauty parlour as make-up mirror is _______.
