Advertisements
Advertisements
प्रश्न
An equilateral triangle ABC is inscribed in a circle with centre O. The measures of ∠BOCis
पर्याय
30°
60°
90°
120°
Advertisements
उत्तर
120°
We are given that an equilateral ΔABC is inscribed in a circle with centre O. We need to find ∠BOC
We have the following corresponding figure:
We are given AB = BC = AC
Since the sides AB, BC, and AC are these equal chords of the circle.
So, the angle subtended by these chords at the centre will be equal.
Hence
`angleAOB + angleBOC + angleAOC = 360`
`angleBOC + angleBOC + angleBOC = 360`
`3angleBOC = 360`
`angleBOC = 360/3`
`angleBOC = 120°`
APPEARS IN
संबंधित प्रश्न
n Fig. 2, PQ and PR are two tangents to a circle with centre O. If ∠QPR = 46°, then ∠QOR equals:
(A) 67°
(B) 134°
(C) 44°
(D) 46°
Points A(–1, y) and B(5, 7) lie on a circle with centre O(2, –3y). Find the values of y. Hence find the radius of the circle.
In fig. a circle touches all the four sides of quadrilateral ABCD with AB = 6cm, BC = 7cm, CD = 4cm. Find AD.
If PT is a tangent to a circle with centre O and PQ is a chord of the circle such that ∠QPT = 70°, then find the measure of ∠POQ.
In the given figure, PA and PB are two tangents to the circle with centre O. If ∠APB = 60° then find the measure of ∠OAB.
Use the figure given below to fill in the blank:
Diameter = 2 x ________
Draw circle with diameter: 8.4 cm
In above case, measure the length of the radius of the circle drawn.
A chord is 12 cm away from the centre of the circle of radius 15 cm. Find the length of the chord
The ______________ is the longest chord of a circle
In the adjoining figure, AC is a diameter of the circle. AP = 3 cm and PB = 4 cm and QP ⊥ AB. If the area of ΔAPQ is 18 cm2, then the area of shaded portion QPBC is ______.
