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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता ८

A part of circumference of a circle is called as _______

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प्रश्न

A part of circumference of a circle is called as _______

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उत्तर

A part of circumference of a circle is called as an arc

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पाठ 2: Measurements - Exercise 2.1 [पृष्ठ ५८]

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सामाचीर कलवी Mathematics [English] Class 8 TN Board
पाठ 2 Measurements
Exercise 2.1 | Q 1. (v) | पृष्ठ ५८

संबंधित प्रश्‍न

In fig. there are two concentric circles with Centre O of radii 5cm and 3cm. From an
external point P, tangents PA and PB are drawn to these circles if AP = 12cm, find the
tangent length of BP.


In the given figure, if arc AB = arc CD, then prove that the quadrilateral ABCD is an isosceles– trapezium (O is the centre of the circle).


From an external point P, tangents PA and PB are drawn to a circle with center O. If CD is the tangent to the circle at a point E and PA = 14 cm, find the perimeter of ΔPCD.


In the given figure, O is the centre of two concentric circles of radii 4 cm and 6 cm respectively. PA and PB are tangents to the outer and inner circle respectively. If PA = 10 cm, find the length of PB up to one place of decimal.


In the given figure, a circle with center O, is inscribed in a quadrilateral ABCD such that it touches the side BC, AB, AD and CD at points P, Q, R and S respectively. If AB = 29 cm, AD = 23 cm, ∠B = 90° and DS = 5 cm then find the radius of the circle.


Find the length of the chord of a circle in the following when: 

Radius is 13 cm and the distance from the centre is 12 cm 


The center of a circle is at point O and its radius is 8 cm. State the position of a point P (point P may lie inside the circle, on the circumference of the circle, or outside the circle), when:

(a) OP = 10.6 cm

(b) OP = 6.8 cm

(c) OP = 8 cm


AB is a diameter of a circle and AC is its chord such that ∠BAC = 30°. If the tangent at C intersects AB extended at D, then BC = BD.


In the following figure, if ∠ABC = 20º, then ∠AOC is equal to ______.


On a common hypotenuse AB, two right triangles ACB and ADB are situated on opposite sides. Prove that ∠BAC = ∠BDC.


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