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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता ९

In the figure, O is the centre of a circle and diameter AB bisects the chord CD at a point E such that CE = ED = 8 cm and EB = 4 cm. The radius of the circle is

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प्रश्न

In the figure, O is the centre of a circle and diameter AB bisects the chord CD at a point E such that CE = ED = 8 cm and EB = 4 cm. The radius of the circle is

पर्याय

  • 8 cm

  • 4 cm

  • 6 cm

  • 10 cm

MCQ
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उत्तर

10 cm

Explanation;

Hint:

Let the radius OD be x.

OE = OB – BE

= x – 4  ...(OB radius of the circle)

In the ΔOED,

OD2 = OE2 + ED2

x2 = (x – 4)2 + 82

x2 = x2 + 16 – 8x + 64

8x = 80

x = `80/8`

= 10 cm

Radius of the circle = 10 cm.

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पाठ 4: Geometry - Exercise 4.7 [पृष्ठ १८२]

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सामाचीर कलवी Mathematics [English] Class 9 TN Board
पाठ 4 Geometry
Exercise 4.7 | Q 15 | पृष्ठ १८२

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