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प्रश्न
Allyl chloride is hydrolysed more readily than n-propyl chloride. Why?
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उत्तर
Allyl chloride shows high reactivity because the carbocation formed by hydrolysis is stabilised by resonance while no such stabilisation of carbocation exists in the case of n-propyl chloride.
संबंधित प्रश्न
Chlorobenzene is extremely less reactive towards a nucleophilic substitution reaction. Give two reasons for the same.
Write the final product(s) in each of the following reactions:
The presence of nitro group (−NO2) at o/p positions increases the reactivity of haloarenes towards nucleophilic substitution reactions.
How the following conversion can be carried out?
Chlorobenzene to p-nitrophenol
Give reasons:
The dipole moment of chlorobenzene is lower than that of cyclohexyl chloride.
Write the product formed on reaction of D-glucose with Br2 water.
Out of (CH3)3 C-Br and (CH3)3 C-I, which one is more reactive towards SN1 and why?
Assertion: Presence of a nitro group at ortho or para position increases the reactivity of haloarenes towards nucleophilic substitution.
Reason: Nitro group, being an electron-withdrawing group decreases the electron density over the benzene ring.
Arrange the following compounds in increasing order of rate of reaction towards nucleophilic substitution.
| (a) |  |
| (b) |  |
| (c) |  |
Arrange the following compounds in increasing order of rate of reaction towards nucleophilic substitution.
| (a) |  |
| (b) |  |
| (c) |  |
Arrange the following compounds in increasing order of rate of reaction towards nucleophilic substitution.
| (a) |  |
| (b) |  |
| (c) |  |
Arrange the following compounds in increasing order of rate of reaction towards nucleophilic substitution.
| (a) |  |
| (b) |  |
| (c) |  |
Haloarenes are less reactive than haloalkanes and haloalkenes. Explain.
\[\ce{C6H12O6 ->[(Zymase)] A ->[NaOH][\Delta] B + CHI3}\]
The number of carbon atoms present in the product B is:
Identify the final product [D] obtained in the following sequence of reactions.
\[\ce{CH3CHO \underset{ii) H2O+}{\overset{i) LiAlH4}{->}} [A] \underset{\triangle}{\overset{H2SO4}{->}} [B]}\]
