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प्रश्न
Account for the following :
Ti4+ is colourless whereas V4+ is coloured in an aqueous solutions.
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उत्तर
`"_22 Ti = [Ar]3d 4s^2`
22Ti4+ = [Ar]3d3 4S0 → No electrons for excitation so 4 Ti4+ is colourless.
23V = [Ar]3d3 4s2
V4+ = 3d1 4s0 → 1 electron is there for excitation and it impart blue colour in aquous
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संबंधित प्रश्न
How is the variability in oxidation states of transition metals different from that of the non-transition metals? Illustrate with examples.
Calculate the number of unpaired electrons in the following gaseous ions:
Mn3+, Cr3+, V3+ and Ti3+. Which one of these is the most stable in an aqueous solution?
Why does the density of transition elements increase from Titanium to Copper? (at. no. Ti = 22, Cu = 29)
Why do transition elements show variable oxidation states ? In 3d series (Sc to Zn), which elements shows the maximum number of oxidation state and why ?
Explain why Zn2+ salts are white whereas Cu2+ salts are coloured.
Maximum oxidation state is shown by ____________.
Which of the following ions show higher spin only magnetic moment value?
(i) \[\ce{Ti^3+}\]
(ii) \[\ce{Mn2+}\]
(iii) \[\ce{Fe2+}\]
(iv) \[\ce{Co3+}\]
Although fluorine is more electronegative than oxygen, but the ability of oxygen to stabilise higher oxidation states exceeds that of fluorine. Why?
The second and third rows of transition elements resemble each other much more than they resemble the first row. Explain why?
Account for the following:
Ce4+ is a strong oxidising agent.
