Advertisements
Advertisements
प्रश्न
A uniform metre rule rests horizontally on a knife-edge at the 60 cm mark when a mass of 10 gram is suspended from one end. At which end must this mass be suspended? What is the mass of the rule?
Advertisements
उत्तर
Let M gram be the mass of the rule. Since the density of the rule is uniform, its weight Mg will act at its middle point i.e., at the 50 cm mark (Fig.).
The weight of the rule produces an anti-clockwise moment about the knife-edge O. In order to balance it, 10-gram mass is to be suspended at the end B, to produce a clockwise moment.
From the principle of moments,
Anti-clockwise moment = Clockwise moment
Mg × (60 – 50) = 10 g × (100-60)
or Mg × 10 = 10 g × 40
∴ M = 40 gram
संबंधित प्रश्न
A spanner of length 10 cm is used to open a nut by applying a minimum force of 5.0 N. Calculate the moment of force required.
Classify the following amongst contact and non-contact force.
force of tension in a string
Write an expression for the change in momentum of a body of mass m moving with velocity v if v << c.
State the relationship between force, mass and acceleration. Draw graphs showing the relationship between Acceleration and mass for a constant force.
A car of mass 600 kg is moving with a speed of 10 m-1 while a scooter of mass 80 kg is moving with speed of 50 m s-1. which vehicle will require more force to stop it in the (1) same interval of time (2) same distance
A spanner (or wrench) has a long handle. Why?
Two forces each of magnitude 10 N act vertically upwards and downwards respectively at the two ends A and B of a uniform rod of length 4 m which is pivoted at its midpoint O as shown in the figure. Determine the magnitude of the resultant moment of forces about the pivot O.
One joule is the amount of work done when a force of ......... moves a body through a distance of .......
Define non-contact forces.
Give any two effects of a force on a non-rigid body.
