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प्रश्न
Two forces each of magnitude 10 N act vertically upwards and downwards respectively at the two ends A and B of a uniform rod of length 4 m which is pivoted at its midpoint O as shown in the figure. Determine the magnitude of the resultant moment of forces about the pivot O.
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उत्तर
F = 10 N on each side
distance of each force from O = 2m
Both are clockwise moments
i.e. 10 N × 2m + 10 N × 2m
= 20 N m + 20 N m
= 40 N m
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संबंधित प्रश्न
A half metre rod is pivoted at the centre with two weights of 20gf and 12gf suspended at a perpendicular distance of 6 cm and 10 cm from the pivot respectively as shown below.
1) Which of the two forces acting on the rigid rod causes clockwise moment?
2) Is the rod in equilibrium?
3) The direction of 20 kgf force is reversed. What is the magnitude of the resultant moment of the forces on the rod?
State the S.I. unit of moment of force.
Name of S.I. unit of momentum.
Give two examples of a couple's actions in our daily life.
Define the moment of force.
In a beam balance when the beam is balanced in a horizontal position, it is in ________ equilibrium.
How does the distance of separation between two bodies affect the magnitude of the non-contact force between them?
The perpendicular distance between the point of application of force and turning point is 1.75 m when a force of 80 N acts on a rigid body. Calculate the moment of force.
Assertion & Reasoning
- Assertion: The sum of the clockwise moments is equal to the sum of the anticlockwise moments.
- Reason: The principle of conservation of momentum is valid if the external force on the system is zero.
