Advertisements
Advertisements
प्रश्न
Two forces each of magnitude 10 N act vertically upwards and downwards respectively at the two ends A and B of a uniform rod of length 4 m which is pivoted at its midpoint O as shown in the figure. Determine the magnitude of the resultant moment of forces about the pivot O.

Advertisements
उत्तर
F = 10 N on each side
distance of each force from O = 2m
Both are clockwise moments
i.e. 10 N × 2m + 10 N × 2m
= 20 N m + 20 N m
= 40 N m
APPEARS IN
संबंधित प्रश्न
In a door, handle is provided ......... from the hinges.
How does the effect of force differ when it is applied on a rigid body?
Sleepers are used below the rails.
A nut is opened by a wrench of length 10 cm. if the least force required is 5.0 N. find the moment of force needed to turn the nut.
Classify the following amongst contact and non-contact forces.
magnetic force
The diagram shows a uniform metre rule weighing 100gf, pivoted at its centre O. Two weights 150gf and 250gf hang from the point A and B respectively of the metre rule such that OA = 40 cm and OB = 20 cm. Calculate :
the total clockwise moment about O

Two unlike forces (parallel) of 10 N and 25 N act at a distance of 12 cm. from each other. Find the point about which the body balance.
The perpendicular distance between the point of application of force and turning point is 1.75 m when a force of 80 N acts on a rigid body. Calculate the moment of force.
Calculate the length of arm of couple, if a force of 13 N produces a moment of couple of 14.3 Nm.
Assertion & Reasoning
- Assertion: The sum of the clockwise moments is equal to the sum of the anticlockwise moments.
- Reason: The principle of conservation of momentum is valid if the external force on the system is zero.
