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प्रश्न
A solenoid of length π m and 5 cm in diameter has winding of 1000 turns and carries a current of 5 A. Calculate the magnetic field at its center along the axis.
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उत्तर
Data: L= 3.142 m, N = 1000, l = 5A,
μ0 = 4π × 10-7 T m/A
The magnetic induction,
B = `mu_0 "nI" = mu_0 ("N"/"L")"I"`
`= (4pi xx 10^-7)(1000/3.142)(5) = (20 xx 3.142 xx 10^-4)/3.142`
= 2 × 10-3 T
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