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प्रश्न
A solenoid of length 50 cm of the inner radius of 1 cm and is made up of 500 turns of copper wire for a current of 5 A in it. What will be the magnitude of the magnetic field inside the solenoid?
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उत्तर
The magnitude of the magnetic field inside the solenoid,
B = `mu_0"N"/"l""i" = 4pi xx 10^-7 xx 500/0.5 xx 5 = 6.284 xx 10^-3`T
संबंधित प्रश्न
A solenoid of length π m and 5 cm in diameter has winding of 1000 turns and carries a current of 5 A. Calculate the magnetic field at its center along the axis.
A toroid of a central radius of 10 cm has windings of 1000 turns. For a magnetic field of 5 × 10-2 T along its central axis, what current is required to be passed through its windings?
What is Solenoid?
What is Toroid?
Magnetic field lines can be entirely confined within the core of a toroid, but not within a straight solenoid Why?
Using Ampere's Law, derive an expression for the magnetic induction inside an ideal solenoid carrying a steady current.
A winding wire which is used to frame a solenoid can bear a maximum of 20 A current. If the length of the solenoid is 80 cm and its cross-sectional radius is 3 cm, then the required length of winding wire is ______ (B = 0.2 T)
Two current-carrying coils have radii r and 4r and have same magnetic induction at their centres. The ratio of voltage applied across them is ______.
A 600 turn coil of effective area 0.05 m2 is kept perpendicular to a magnetic field 4 x 10-5 T. When the plane of the coil is rotated by 90° around any of its coplanar axis in 0.1 s, the e.m.f. induced in the coil will be: ____________.
A solenoid of 1.5 m length and 4 cm diameter possesses 20 turns per m. A current of 6 A is flowing through it. The magnetic induction at axis inside the solenoid is ____________.
A proton is projected with a uniform velocity 'v' along the axis of a current carrying solenoid, then ____________.
The space within a current carrying toroid is filled with a m metal of susceptibility 16.5 x 10-6. The percentage increase in the magnetic field B is ____________.
Magnetic induction due to a toroid does not depend upon ______.
A winding wire is used to prepare a solenoid that can bear a maximum current of 10A. If the length of a solenoid is 80 cm and its cross-sectional radius is 3 cm, the required length of winding wire is ____________.
(magnetic field B = 0.2 T, µ0 = 4 x 10-7 SI units)
A charged particle carrying a charge 'q' and moving with velocity V, enters into a solenoid carrying a current T, along its axis. If 'B' is the magnetic induction along the axis of a solenoid, then the force 'F' acting on the charged particle will be ____________.
A long solenoid has 200 turns per cm and carries a current of 2.5 A. The magnetic field at the center is ______. (µ0 = 4π × 10-7 Wb/m-A)
A straight solenoid has 50 turns per cm in primary and 200 turns per cm in the secondary. The area of cross-section of the solenoid is 4 cm2. The mutual inductance is ______.
Obtain an expression for magnetic induction of a toroid of ‘N’ turns about an axis passing through its centre and perpendicular to its plane.
A conducting rod along the equator is 1 m long and carries a current of 15 A from east to west. The magnitude of Earth's magnetic field at the equator is `4/3 xx 10^(-4)` T. The magnitude and direction of the force on the rod are ______.
A current of 10 A passes through a coil having 5 turns and produces magnetic field at the centre of the coil having magnitude 0.5 x 10-4 T. Calculate diameter of the coil.
(µ0 = 4π x 10-7 Wb/Am)
