मराठी

A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl. Assume [Assume π=227]

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प्रश्न

A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.

`["Assume "pi = 22/7]`

बेरीज
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उत्तर

Inner radius of hemispherical bowl = 5 cm

The thickness of the bowl = 0.25 cm

∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm

= 5.25 cm

Outer curved surface area of hemispherical bowl = 2πr2

= `2xx22/7 (5.25  cm)^2`

= `173.25  cm^2`

Therefore, the outer curved surface area of the bowl is 173.25 cm2.

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पाठ 11: Surface Area and Volumes - EXERCISE 11.2 [पृष्ठ १४५]

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एनसीईआरटी Mathematics [English] Class 9
पाठ 11 Surface Area and Volumes
EXERCISE 11.2 | Q 8. | पृष्ठ १४५

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