Advertisements
Advertisements
प्रश्न
A solid is in the form of a cone standing on a hemi-sphere with both their radii being equal to 8 cm and the height of cone is equal to its radius. Find, in terms of π, the volume of the solid.
Advertisements
उत्तर
Given, Radius of each cone and hemi-sphere (r) = 8 cm
Height of cone (h) = r = 8 cm

∴ Volume of solid
= `1/3pir^2h + 2/3pir^3`
= `1/3pir^2(h + 2r) cm^3`
= `1/3pi xx 8 xx 8(8 + 2 xx 8) cm^3`
= `64/3 pi(8 + 16) cm^3`
= `64/3pi xx 24`
= 512 π cm3
APPEARS IN
संबंधित प्रश्न
The surface area of a sphere is 2464 cm2, find its volume.
The volume of a sphere is 38808 cm3; find its diameter and the surface area.
How many spherical bullets can be made out of a solid cube of lead whose edge measures 44 cm, each bullet being 4 cm in diameter?
The largest sphere is cut off from a cube of side 6 cm. The volume of the sphere will be
If the ratio of volumes of two spheres is 1 : 8, then the ratio of their surface areas is
Find the volume of the hollow sphere whose inner diameter is 8 cm and the thickness of the material of which it is made is 1 cm .
From a rectangular solid of metal 42 cm by 30 cm by 20 cm, a conical cavity of diameter 14 cm and depth 24 cm is drilled out. Find: the volume of remaining solid
From a rectangular solid of metal 42 cm by 30 cm by 20 cm, a conical cavity of diameter 14 cm and depth 24 cm is drilled out. Find: the weight of the material drilled out if it weighs 7 gm per cm3.
The volume of a sphere is 905 1/7 cm3, find its diameter.
A manufacturing company prepares spherical ball bearings, each of radius 7 mm and mass 4 gm. These ball bearings are packed into boxes. Each box can have a maximum of 2156 cm3 of ball bearings. Find the:
- maximum number of ball bearings that each box can have.
- mass of each box of ball bearings in kg.
(Use π = `22/7`)
