Advertisements
Advertisements
प्रश्न
A force of 10 N acts on a body of mass 2 kg for 3 s, initially at rest. Calculate : Change in momentum of the body.
Advertisements
उत्तर
Force, F = 10 N
Mass, m = 2 kg
Time, t = 3 s
Initial velocity, u = 0 m/s.
Change in momentum = Final momentum - initial momentum
Δp = mv - mu.
Or, Δp = m (v - u).
Or, Δp = 2 (15 - 0) = 30 kg m/s-1
APPEARS IN
संबंधित प्रश्न
When a horse pulls a cart, the force that helps the horse to move forward is the force exerted by
A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block has a magnitude.
Consider the Atwood machine of the previous problem. The larger mass is stopped for a moment, 2.0 s after the system is set into motion. Find the time that elapses before the string is tight again.
Find the acceleration of the 500 g block in the following figure.
A block A can slide on a frictionless incline of angle θ and length l, kept inside an elevator going up with uniform velocity v in the following figure. Find the time taken by the block to slide down the length of the incline if it is released from the top of the incline.
Use Newton's second law of motion to explain the following instance :
A cricketer pulls his hands back while catching a fast moving cricket ball .
A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate: The velocity acquired by the body.
Define Newton’s second law of motion.
Name the physical quantity which equals the rate of change of linear momentum.
Why is catching a slow-moving ball easier than catching a fast-moving ball?
