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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

A first order reaction has a rate constant 1.15 × 10^−3 s−1. How long will 5 g of this reactant take to reduce to 3 g?

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प्रश्न

A first order reaction has a rate constant 1.15 × 10−3 s1. How long will 5 g of this reactant take to reduce to 3 g?

संख्यात्मक
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उत्तर

For a first-order reaction,

a = 5 g

(a – x) = 3 g

k = 1.15 × 10−3 s1

t = `2.303/k log  a/((a - x))`

= `2.303/(1.15 xx 10^-3) log  (5)/(3)`

= 2.00 × 103 (log 5 − log 3)

= 2.00 × 103 (0.6990 − 0.4771)

= 2.00 × 103 × 0.2219

= 443.8

≈ 444 S

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पाठ 3: Chemical Kinetics - Intext Questions [पृष्ठ ७८]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 3 Chemical Kinetics
Intext Questions | Q 3.5 | पृष्ठ ७८

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