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प्रश्न
A current of 0.2 A flows through a conducting wire for 5 minutes. How much charge will flow?
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उत्तर
Given: I = 0.2A, t = 5 minute = 5 × 60s = 300s.
Charge Q = I × t = 0.2 × 300 = 60 C.
संबंधित प्रश्न
The values of current I flowing in a given resistor for the corresponding values of potential difference V across the resistor are given below:
| I (amperes) | 0.5 | 1.0 | 2.0 | 3.0 | 4.0 |
| V (volts) | 1.6 | 3.4 | 6.7 | 10.2 | 13.2 |
Plot a graph between V and I and calculate the resistance of that resistor.
Calculate the quantity of heat produced in a 20 Ω resistor carrying 2.5 A current in 5 minutes.
State whether the resistivity of a wire changes with the change in the thickness of the wire.
A resistance of 20 ohms has a current of 2 amperes flowing in it. What potential difference is there between its ends?
b. The values of potential difference V applied across a resistor and the correponding values of current I flowing in the resistor are given below:
| Potential difference, V (in volts) | : | 2.5 | 5.0 | 10.0 | 15.0 | 20.0 | 25.0 |
| Current, I (in amperes) | : | 0.1 | 0.2 | 0.4 | 0.6 | 0.8 | 1.0 |
Plot a graph between V and I, and calculate the resistance of the resistor.
c. Name the law which is illustrated by the above V-I graph.
Write proper word from the following group of words in the blank.
(magnetism, 4.5V, 3.0V, gravitational attraction, potential difference, potential, higher, lower, 0V)
Water in the waterfall flows from a higher level to the lower level because of ______.
Write an expression for the electrical power spent in flow of current through a conductor in terms of resistance and potential difference.
Draw a graph of Potential difference (V) versus Current (I) for an ohmic resistor. How can you find the resistance of the resistor from this graph?
An electric bulb draws 0.5 A current at 3.0 V. Calculate the resistance of the filament of the bulb.
Find the potential difference required to flow a current of 300 mA in a wire of resistance 20 Ω.
