Advertisements
Advertisements
प्रश्न
A current of 1.6 mA flows through a conductor. If charge on an electron is –1.6 × 10-19 coulomb, find the number of electrons that will pass each second through the cross section of that conductor.
Advertisements
उत्तर
Current, I = 1.6 mA = 1.6 × 10-3 A
Charge, Q = -1.6 × 10-19 coulomb
t = 1 sec
Charge flowing through the conductor in one second
I = `"Q"/"t"`
Q = I × t
Substituting the values in the formula above we get,
Q = 1.6 × 10-3 × 1
= 1.6 × 10-3
No. of electrons = `(1.6 xx10^-3)/(1.6xx10^-19)`
= `10^16`
Therefore, the number of electrons that will pass each second through the cross section of that conductor = 1016
संबंधित प्रश्न
Name a device that helps to maintain a potential difference across a conductor.
The values of current I flowing in a given resistor for the corresponding values of potential difference V across the resistor are given below:
| I (amperes) | 0.5 | 1.0 | 2.0 | 3.0 | 4.0 |
| V (volts) | 1.6 | 3.4 | 6.7 | 10.2 | 13.2 |
Plot a graph between V and I and calculate the resistance of that resistor.
What is the unit of electric charge?
Name a device which helps to maintain potential difference across a conductor (say, a bulb).
What current will be taken by a 920 W appliance if the supply voltage is 230 V?
How is the electric potential difference between the two points defined? State its S.I. unit.
Define the term ‘volt’.
Explain why potential difference is always less than the e.m.f. of a cell?
In the figure given below, A, B and C are three ammeters. The ammeter B reads 0.5A. (All the ammeters have negligible resistance.)
Calculate:
(i) the readings in the ammeters A and C.
(ii) the total resistance of the circuit.
Two bulbs are marked 100 W, 220 V and 60 W, 110 V. Calculate the ratio of their resistances.
