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A cubical block of ice floating in water has to support a metal piece weighing 0.5 kg. Water can be the minimum edge of the block so that it does not sink in water? Specific gravity of ice = 0.9.

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प्रश्न

A cubical block of ice floating in water has to support a metal piece weighing 0.5 kg. Water can be the minimum edge of the block so that it does not sink in water? Specific gravity of ice = 0.9. 

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उत्तर

Given:
Specific gravity of ice, ρice = 0.9 gm/cc
Weight of the metal piece, m = 500 g
Density of water,  \[\rho_w\] = 103 kg/m3

Let x be the minimum edge of the ice block in cm.
We have:
mg + Wice = U 
Here,
U = Upward thrust
Wice = Weight of the ice

\[\text{Thus, we have: }\]

\[0 . 5 \times \text{ g + x}^3 \times \rho_{\text{ ice }} \times \text{ g = x} ^3 \times \rho_w \times g \left[ \text{ Volume of the liquid displaced = x}^3 \right]\]

\[ \Rightarrow 0 . 5 \times {10}^3 + x^3 \times (0 . 9) = x^3 \times 1\]

\[ \Rightarrow x^3 \times (0 . 1) = (0 . 5) \times {10}^3 \]

\[ \Rightarrow x^3 = 5 \times {10}^3 \]

\[ \Rightarrow x = 17 . 09 \text{ cm}\]

\[ \Rightarrow x = 17 \text{ cm }\]

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पाठ 13: Fluid Mechanics - Exercise [पृष्ठ २७४]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 13 Fluid Mechanics
Exercise | Q 13 | पृष्ठ २७४

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