Advertisements
Advertisements
प्रश्न
A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was Rs 90, find the number of articles produced and the cost of each article.
Advertisements
उत्तर
Let the number of articles produced be x.
Therefore, cost of production of each article = Rs (2x + 3)
It is given that the total production is Rs 90.
∴ x(2x + 3) = 0
⇒ 2x2 + 3x − 90 = 0
⇒ 2x2 + 15x −12x − 90 = 0
⇒ x(2x + 15) −6(2x + 15) = 0
⇒ (2x + 15)(x − 6) = 0
Either 2x + 15 = 0 or x − 6 = 0
⇒ `x = (−15)/2` or x = 6
Since the number cannot be negative, therefore, x = 6.
So, the number of articles = 6
Cost of each article = 2 × 6 + 3 = Rs 15.
APPEARS IN
संबंधित प्रश्न
Solve for x
`(2x)/(x-3)+1/(2x+3)+(3x+9)/((x-3)(2x+3)) = 0, x!=3,`
Solve for x :
`2/(x+1)+3/(2(x-2))=23/(5x), x!=0,-1,2`
Find the roots of the following quadratic equation by factorisation:
`2x^2 – x + 1/8 = 0`
Solve the following quadratic equations by factorization:
`(x+3)/(x-2)-(1-x)/x=17/4`
Solve the following quadratic equations by factorization:
a2b2x2 + b2x - a2x - 1 = 0
A two digit number is 4 times the sum of its digits and twice the product of its digits. Find the number.
Solve x2 – 4x – 12 =0; when x ∈ I
Solve the following quadratic equation by factorisation.
x2 + x – 20 = 0
Solve the following quadratic equation by factorisation.
25m2 = 9
Find the value of p for which the quadratic equation
\[\left( p + 1 \right) x^2 - 6(p + 1)x + 3(p + 9) = 0, p \neq - 1\] has equal roots. Hence, find the roots of the equation.
Disclaimer: There is a misprinting in the given question. In the question 'q' is printed instead of 9.
If \[1 + \sqrt{2}\] is a root of a quadratic equation will rational coefficients, write its other root.
The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages was 124. Determine their present ages.
The hypotenuse of a right-angled triangle is 17cm. If the smaller side is multiplied by 5 and the larger side is doubled, the new hypotenuse will be 50 cm. Find the length of each side of the triangle.
Solve equation using factorisation method:
`x + 1/x = 2.5`
In each of the following, determine whether the given values are solution of the given equation or not:
x2 - 3`sqrt(3)` + 6 = 0; x = `sqrt(3)`, x = -2`sqrt(3)`
Solve the following equation by factorization
`(2)/(3)x^2 - (1)/(3)x` = 1
Solve the following equation by factorization
`x^2 - (1 + sqrt(2))x + sqrt(2)` = 0
A two digit number contains the bigger at ten’s place. The product of the digits is 27 and the difference between two digits is 6. Find the number.
The polynomial equation x(x + 1) + 8 = (x + 2) (x – 2) is:
