Advertisements
Advertisements
प्रश्न
The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages was 124. Determine their present ages.
Advertisements
उत्तर
Let the present age of the man be M years and his son's age be 5 years. Then, as per the question description,
M + 5 = 45 ...... (i)
{M - 5)(5 - 5) = 124 ...... (ii)
From (i), we get: M=45-5 ...... (iii)
Putting (iii) in (ii), we get: {45 - 5 - 5) (5 - 5) = 124
⇒ (40 - 5)(5 - 5) =124
⇒ S2 - 45 S + 324 = 0
⇒ S2 - 9S - 36S + 324 = 0
⇒ S (5 - 9) - 36(5 - 9) = 0
⇒ S = 9 , 36
⇒ S = 9 years and hence , M = 36 years
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
`(x-3)/(x+3 )+(x+3)/(x-3)=2 1/2`
Find the two consecutive positive even integers whose product is 288.
The sum of two natural numbers is 15 and the sum of their reciprocals is `3/10`. Find the numbers.
The sum of two natural numbers is 20 while their difference is 4. Find the numbers.
Solve the following quadratic equations by factorization: \[\frac{x - 4}{x - 5} + \frac{x - 6}{x - 7} = \frac{10}{3}; x \neq 5, 7\]
Solve the following equation: 2x2 - x - 6 = 0
A two digit number is such that the product of the digits is 14. When 45 is added to the number, then the digit are reversed. Find the number.
The speed of a boat in still water is 15km/ hr. It can go 30km upstream and return downstream to the original point in 4 hours 30 minutes. Find the speed of the stream.
A natural number, when increased by 12, equals 160 times its reciprocal. Find the number.
Using quadratic formula find the value of x.
p2x2 + (p2 – q2)x – q2 = 0
