Advertisements
Advertisements
प्रश्न
A two digit number contains the bigger at ten’s place. The product of the digits is 27 and the difference between two digits is 6. Find the number.
Advertisements
उत्तर
Let unit’s digit = x
then tens digit = x + 6
Number = x + 10(x + 6)
= x + 10x + 60
= 11x + 60
According to the condition,
x(x + 6) = 27
⇒ x2 + 6x - 27 = 0
⇒ x2 + 9x - 3x - 27 = 0
⇒ x(x + 9) - 3(x + 9) = 0
⇒ (x + 9)(x - 3) = 0
Either x + 9 = 0,
then x = -9,
but it is not possible as it is negative.
or
x - 3 = 0,
then x = 3
∴ Number
= 11x + 60
= 11 × 3 + 60
= 33 + 60
= 93
APPEARS IN
संबंधित प्रश्न
If an integer is added to its square, the sum is 90. Find the integer with the help of quadratic equation.
A two digits number is such that the product of the digits is 12. When 36 is added to the number, the digits inter change their places determine the number.
The perimeter of a rectangular field is 82 m and its area is 400 m2. Find the breadth of the rectangle.
Solve:
`(x/(x + 2))^2 - 7(x/(x + 2)) + 12 = 0; x != -2`
Solve the following quadratic equations by factorization:
`(2x – 3)^2 = 49`
Solve the following equation : `"ax"^2 + (4"a"^2 - 3"b")"x" - 12"ab" = 0`
Solve the following equation:
`("x" + 1)/("x" - 1) - ("x" - 1)/("x" + 1) = 5/6 , "x" ≠ -1,1`
Solve the following equation: a2b2x2 + b2x - a2x - 1 = 0
In each of the following, determine whether the given values are solution of the given equation or not:
`a^2x^2 - 3abx + 2b^2 = 0; x = a/b, x = b/a`.
Solve the following equation by factorisation :
2x2 + ax – a2= 0
