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प्रश्न
Solve the following quadratic equation by factorization:
`sqrt(6)x^2 - 4x - 2sqrt(6) = 0`
बेरीज
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उत्तर
`sqrt(6)x^2 - 4x - 2sqrt(6) = 0`
Here `a = sqrt(6), b = -4` and `c = -2sqrt(6)`
Then `x = (-b +- sqrt(b^2 - 4ac))/(2a)`
= `(-(-4) +- sqrt((-4)^2 - 4(sqrt(6))(-2sqrt(6))))/(2(sqrt(6))`
= `(4 +- sqrt(64))/(2sqrt(6))`
= `(4 +- 8)/(2sqrt(6))`
= `(4 + 8)/(2sqrt(6))` and `(4 - 8)/(2sqrt(6))`
= `6/sqrt(6)` and `(-2)/sqrt(6)`
= `sqrt(6)` and `(-sqrt(6))/3`
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