Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation by factorization:
`sqrt(6)x^2 - 4x - 2sqrt(6) = 0`
Advertisements
उत्तर
`sqrt(6)x^2 - 4x - 2sqrt(6) = 0`
Here `a = sqrt(6), b = -4` and `c = -2sqrt(6)`
Then `x = (-b +- sqrt(b^2 - 4ac))/(2a)`
= `(-(-4) +- sqrt((-4)^2 - 4(sqrt(6))(-2sqrt(6))))/(2(sqrt(6))`
= `(4 +- sqrt(64))/(2sqrt(6))`
= `(4 +- 8)/(2sqrt(6))`
= `(4 + 8)/(2sqrt(6))` and `(4 - 8)/(2sqrt(6))`
= `6/sqrt(6)` and `(-2)/sqrt(6)`
= `sqrt(6)` and `(-sqrt(6))/3`
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
`x^2-(sqrt3+1)x+sqrt3=0`
Solve the following quadratic equations by factorization:
`(x-1)/(x-2)+(x-3)/(x-4)=3 1/3`, x ≠ 2, 4
Divide 29 into two parts so that the sum of the squares of the parts is 425.
Solve the following quadratic equation by factorisation.
m2 - 11 = 0
If sin α and cos α are the roots of the equations ax2 + bx + c = 0, then b2 =
Solve the following equation :
`1/(("x" - 1)(x - 2)) + 1/(("x" - 2)("x" - 3)) + 1/(("x" - 3)("x" -4)) = 1/6`
Solve equation using factorisation method:
2(x2 – 6) = 3(x – 4)
Five years ago, a woman’s age was the square of her son’s age. Ten years hence, her age will be twice that of her son’s age. Find:
- the age of the son five years ago.
- the present age of the woman.
In each of the following, determine whether the given values are solution of the given equation or not:
`a^2x^2 - 3abx + 2b^2 = 0; x = a/b, x = b/a`.
Solve the following quadratic equation by factorization method.
3p2 + 8p + 5 = 0
