Question

Solve the following quadratic equation by factorization:

`sqrt(6)x^2 - 4x - 2sqrt(6) = 0`

Answer 1

`sqrt(6)x^2 - 4x - 2sqrt(6) = 0`

Here `a = sqrt(6), b = -4` and `c = -2sqrt(6)`

Then `x = (-b +- sqrt(b^2 - 4ac))/(2a)`

= `(-(-4) +- sqrt((-4)^2 - 4(sqrt(6))(-2sqrt(6))))/(2(sqrt(6))`

= `(4 +- sqrt(64))/(2sqrt(6))`

= `(4 +- 8)/(2sqrt(6))`

= `(4 + 8)/(2sqrt(6))` and `(4 - 8)/(2sqrt(6))`

= `6/sqrt(6)` and `(-2)/sqrt(6)`

= `sqrt(6)` and `(-sqrt(6))/3`