Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation by factorisation:
2x2 + ax - a2 = 0 where a ∈ R.
Advertisements
उत्तर
2x2 + ax - a2 = 0
⇒ 2x2 + 2ax - ax - a2 = 0
⇒ 2x(x + a) -a(x + a) = 0
⇒ (x = a) (2x - a) = 0
⇒ x + a = 0 or 2x - a = 0
⇒ x = -a and x = `a/(2)`.
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
(x − 4) (x + 2) = 0
Solve the following quadratic equations by factorization:
4x2 + 4bx - (a2 - b2) = 0
Solve the following quadratic equations by factorization:
3x2 − 14x − 5 = 0
Solve the following quadratic equations by factorization:
abx2 + (b2 – ac)x – bc = 0
The perimeter of a rectangular field is 82 m and its area is 400 m2. Find the breadth of the rectangle.
Find the tow consecutive positive odd integer whose product s 483.
Solve equation using factorisation method:
`4/(x + 2) - 1/(x + 3) = 4/(2x + 1)`
In each of the following determine whether the given values are solutions of the equation or not.
6x2 - x - 2 = 0; x = `-(1)/(2), x = (2)/(3)`
In each of the following, determine whether the given values are solution of the given equation or not:
2x2 - x + 9 = x2 + 4x + 3; x = 2, x = 3
The difference between the squares of two numbers is 45. The square of the smaller number is 4 times the larger number. Determine the numbers.
