Question

In each of the following, determine whether the given values are solution of the given equation or not:
x² + x + 1 = 0; x = 0; x = 1

Answer 1

Now Substitute x = 0 in given equation
L.H.S. = (0)² + 0 + 1 ≠ 0 ≠ R.H.S.
on substituting x = 1 in L.H.S. of given equation
⇒ (1)² + 1 + 1 ≠ 0 ≠ R.H.S.
Hence x = 0 and x = 1 are not solutions of the given equation.