Advertisements
Advertisements
प्रश्न
A certain current liberated 0.504 gm of hydrogen in 2 hours. How many grams of copper can be liberated by the same current flowing for the same time through copper sulphate solution.
पर्याय
31.75
15.8
7.5
63.5
Advertisements
उत्तर
15.8
Explanation:
m1 = 0.504 g
m2 = ?
e1 = 1.008
e2 = 31.77
`"m"_1/"m"_2 = "e"_1/"e"_2`
∴ m2 = `"m"_1/"e"_1 ⋅"e"_2`
= `(0.504 xx 31.77)/1.008`
= 15.885 g
APPEARS IN
संबंधित प्रश्न
Arrange the following metals in the order in which they displace each other from the solution of their salts.
Al, Cu, Fe, Mg and Zn.
A current strength of 3.86 A was passed through molten Calcium oxide for 41minutes and 40 seconds. The mass of Calcium in grams deposited at the cathode is (atomic mass of Ca is 40g/mol and 1F = 96500 C).
Cell equation: \[\ce{A + 2B^- -> A^{2+} + 2B}\]
\[\ce{A^{2+} + 2e^- -> A}\] E0 = +0.34 V and log10 k = 15.6 at 300 K for cell reactions find E0 for \[\ce{B^+ + e^- -> B}\]
Define cathode
Is it possible to store copper sulphate in an iron vessel for a long time?
Given: \[\ce{E^0_{{Cu^{2+}|{Cu}}}}\] = 0.34 V and \[\ce{E^0_{{Fe^{2+}|{Fe}}}}\] = −0.44 V
Write a note on sacrificial protection.
Can absolute electrode potential of an electrode be measured?
Cell reaction is spontaneous when
Calculate the λ0m for Cl- ion from the data given below:
∧0m MgCl2 = 258.6 Scm2 mol-1 and λ0m Mg2+ = 106 Scm2 mol-1
State the term for the following:
Two metal plates or wires through which the current enters and leaves the electrolytic cell.
