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प्रश्न
Depict the galvanic cell in which the cell reaction is \[\ce{Cu + 2Ag^+ -> 2Ag + Cu^{2+}}\]
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उत्तर
Anode- Oxidation half-cell: \[\ce{Cu -> Cu^{2+} + 2e-}\]
Cathode- Reduction half-cell: \[\ce{2Ag+ + 2e^{-} -> 2Ag}\]
Overall reaction: \[\ce{Cu + 2Ag+ -> Cu^{2+} + 2Ag}\]
\[\ce{Cu | Cu^{2+} (aq, 1M) || Ag^{+} (aq, 1M) | Ag}\]
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Oxidation-reduction reactions are commonly known as redox reactions. They involve transfer of electrons from one species to another. In a spontaneous reaction, energy is released which can be used to do useful work. The reaction is split into two half-reactions. Two different containers are used and a wire is used to drive the electrons from one side to the other and a Voltaic/Galvanic cell is created. It is an electrochemical cell that uses spontaneous redox reactions to generate electricity. A salt bridge also connects to the half-cells. The reading of the voltmeter gives the cell voltage or cell potential or electromotive force. If \[\ce{E^0_{cell}}\] is positive the reaction is spontaneous and if it is negative the reaction is non-spontaneous and is referred to as electrolytic cell. Electrolysis refers to the decomposition of a substance by an electric current. One mole of electric charge when passed through a cell will discharge half a mole of a divalent metal ion such as Cu2+. This was first formulated by Faraday in the form of laws of electrolysis.
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