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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

A box with a square base is to have an open top. The surface area of the box is 192 sq cm. What should be its dimensions in order that the volume is largest?

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प्रश्न

A box with a square base is to have an open top. The surface area of the box is 192 sq cm. What should be its dimensions in order that the volume is largest?

बेरीज
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उत्तर

Let x cm be the side of square base and h cm be its height.

Then x2 + 4xh = 192

∴ h = `(192 - x^2)/(4x)`                    ...(1)

Let V = `x^2"h"`

= `x^2((192 - x^2)/(4x))`   ...[By (1)]

∴ V = `(1)/(4)(192x - x^3)`

∴ `"dV"/("d"x) = (1)/(4) "d"/("d"x)(192x - x^3)`

= `(1)/(4)(192 xx 1 - 3x^2)`

= `(3)/(4)(64 - x^2)`

and

`("d"^2"V")/("d"x^2) - (3"d")/(4"d"x)(64 - x^2)`

= `(3)/(4)(0 - 2x)`

= `-(3)/(2)x`

For maximum V, `"dV"/("d"x)` = 0

∴ `(3)/(4)(64 - x^2)` = 0

∴ x2 = 64

∴ x = 8                           ...[∵ x > 0]

and

`(("d"^2V)/("d"x^2))_("at" x = 8)`

= `-(3)/(2) xx 8`

= – 12 < 0

∴  by the second derivative test, V is maximum at x = 8.

If x = 8,

h = `(192 - 64)/(4(8)`

= `(128)/(32)`

= 4

Hence, the volume of the box is largest, when the side of square base is 8 cm and its height is 4 cm.

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पाठ 2.2: Applications of Derivatives - Long Answers III

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