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A Battery of E.M.F. 15 V and Internal Resistance 3 Ohm is Connected to Two Resistors of Resistance 3 Ohm and 6 Ohm in Series. Find: (I) the Current Through the Battery, ( - Physics

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प्रश्न

A battery of e.m.f. 15 V and internal resistance 3 ohm is connected to two resistors of resistance 3 ohm and 6 ohm in series. Find:
(i) The current through the battery,
(ii) The p.d. between the terminals of the battery.

संख्यात्मक
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उत्तर

Given, emf, e = 15 v 

Internal resistance, r = 3 `Omega`

Resistance of given two resistors in series, R, = 3 + 6 = 9 `Omega`

(i) Current = `"emf"/"Total resistance of circuit" = 15/(9 + 3) = 15/12` = 1.25 A

(ii) Potential difference= emf - voltage drop= e - (Ir)

Now, voltage drop= current x internal resistance= 1.25 x 3 = 3.75

.·. p.d. = 15 - 3.75= 11.25V

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Current Electricity - Exercise 4.1 iii [पृष्ठ १७५]

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फ्रँक Physics - Part 2 [English] Class 10 ICSE
पाठ 4 Current Electricity
Exercise 4.1 iii | Q 16 | पृष्ठ १७५

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