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Π / 2 ∫ 0 √ 1 − Cos 2 X D X . - Mathematics

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प्रश्न

\[\int\limits_0^{\pi/2} \sqrt{1 - \cos 2x}\ dx .\]
बेरीज
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उत्तर

\[\int_0^\frac{\pi}{2} \sqrt{1 - \cos2x}\ dx\]

\[ = \int_0^\frac{\pi}{2}\sqrt{2 \sin^2 x}\ dx\]

\[ = \int_0^\frac{\pi}{2} \sqrt{2} \sin x\ dx\]

\[ = - \sqrt{2} \left[ \cos x \right]_0^\frac{\pi}{2} \]

\[ = - \left( 0 - \sqrt{2} \right)\]

\[ = \sqrt{2}\]

\[\]

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Definite Integrals
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पाठ 20: Definite Integrals - Very Short Answers [पृष्ठ ११५]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 20 Definite Integrals
Very Short Answers | Q 13 | पृष्ठ ११५

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