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Π / 4 ∫ 0 Cos 4 X Sin 3 X D X

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प्रश्न

\[\int\limits_0^{\pi/4} \cos^4 x \sin^3 x dx\]

बेरीज
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उत्तर

\[\int_0^\frac{\pi}{4} \cos^4 x \sin^3 x d x\]

\[ = \int_0^\frac{\pi}{4} \cos^4 x \sin x \left( 1 - \cos^2 x \right) dx\]

\[ = \int_0^\frac{\pi}{4} \cos^4 x \sin x dx - \int_0^\frac{\pi}{4} \cos^6 x \sin x dx\]

\[ = - \left[ \frac{\cos^5 x}{5} \right]_0^\frac{\pi}{4} + \left[ \frac{\cos^7 x}{7} \right]_0^\frac{\pi}{4} \]

\[ = \frac{- 1}{20\sqrt{2}} + \frac{1}{5} + \frac{1}{56\sqrt{2}} - \frac{1}{7}\]

\[ = \frac{- \sqrt{2}}{40} + \frac{2}{35} + \frac{\sqrt{2}}{112}\]

\[ = \frac{2}{35} - \frac{9\sqrt{2}}{560}\]

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पाठ 19: Definite Integrals - Revision Exercise [पृष्ठ १२१]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 19 Definite Integrals
Revision Exercise | Q 19 | पृष्ठ १२१

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