मराठी
Maharashtra State BoardSSC (English Medium) 10th Standard

Application of Simultaneous Equations

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Estimated time: 17 minutes
Maharashtra State Board: Class 10

Method Selection Guide

Situation Recommended Method Reason
One variable has coefficient 1 Substitution Easy to isolate a variable
Coefficients are simple multiples Elimination Quick cancellation
Equations contain fractions Substitution after simplification Reduces fractional complexity
Equations are in standard form Cross-multiplication or determinants Direct formula-based solution
Graphical interpretation is required Graphical method Shows intersection visually
Maharashtra State Board: Class 10

Word-Problem Translation Guide

English Phrase Mathematical Meaning
“More than” Addition, +
“Less than” Subtraction, −
“Times” Multiplication, ×
“Is”, “equals”, “gives” Equals sign, =
“Sum” Add the quantities
“Difference” Subtract the smaller from the larger
“Perimeter of rectangle” 2(l + b)
“Speed downstream” Speed of boat in still water + speed of stream
“Speed upstream” Speed of boat in still water - speed of stream
“Time” \[ \frac{\text{Distance}}{\text{Speed}} \]
“Two-digit number” 10x + y, where x is tens digit and y is units digit
Maharashtra State Board: Class 10

Problem-Solving Flowchart

Maharashtra State Board: Class 10

Example 1

Sarthak's present age is x years and Sakshi's present age is y years. Frame simultaneous linear equations based on the following conditions:

  1. Sarthak's age is less by 8 than double the age of Sakshi.

  2. The sum of the present ages of Sarthak and Sakshi is 25.

  3. 4 years ago, Sakshi's age was 3 years less than Sarthak's age at that time.
    (Find their present ages using any two suitable conditions).

Solution:

1. Condition 1:

"Sarthak's age is less by 8 than double the age of Sakshi"

Equation: \[ x = 2y - 8 \implies x - 2y = -8 \]

2. Condition 2:

"The sum of the present ages of Sarthak and Sakshi is 25"

Equation: \[ x + y = 25 \]

3. Condition 3:

"4 years ago, Sakshi's age was 3 years less than Sarthak's age at that time"

Calculation: \[ (y - 4) = (x - 4) - 3 \implies y - 4 = x - 7 \]

Equation: \[ x - y = 3 \]

Maharashtra State Board: Class 10

Example 2

A certain amount is equally distributed among certain number of students. Each would get ₹2 less if 10 students were more and each would get ₹6 more if 15 students were less. Find the number of students and the amount distributed.

Solution:

Let the number of students be \[ x \] and amount given to each student be \[ \text{₹}y. \]

\[ \therefore \] Total amount distributed is \[ xy. \]

From the first condition:

\[ (x + 10)(y - 2) = xy \]

\[ \therefore xy - 2x + 10y - 20 = xy \]

\[ \therefore -2x + 10y = 20 \]

\[ \therefore -x + 5y = 10 \ldots (I) \]

From the second condition:

\[ (x - 15)(y + 6) = xy \]

\[ \therefore xy + 6x - 15y - 90 = xy \]

\[ \therefore 6x - 15y = 90 \]

\[ \therefore 2x - 5y = 30 \ldots (II) \]

Adding equations (I) and (II):

\[ \begin{array}{r} -x + 5y = 10 \\ +\;\; 2x - 5y = 30 \\ \hline x = 40 \end{array} \]

Substitute this value of \[ x \] in equation (I):

\[ -x + 5y = 10 \]

\[ \therefore -40 + 5y = 10 \]

\[ \therefore 5y = 50 \]

\[ \therefore y = 10 \]

Final Answer:

Total amount distributed is \[ = xy = 40 \times 10 = \text{₹}400. \]

\[ \therefore \text{₹}400 \] distributed equally among 40 students.

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