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![SCERT Maharashtra solutions for साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड chapter 1 - Gravitation - Shaalaa.com](/images/science-and-technology-part-1-english-standard-10-maharashtra-state-board_6:5f2b1b2038084cf381bfa42c826a928c.jpg "SCERT Maharashtra solutions for साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड chapter 1 - Gravitation")
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Solutions for Chapter 1: Gravitation
Below listed, you can find solutions for Chapter 1 of Maharashtra State Board SCERT Maharashtra for साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड.
SCERT Maharashtra solutions for साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड 1 Gravitation Choose the correct option. [Page 2]
A ______ is necessary to change the speed as well as the direction of motion of an object.
force
inertia
momentum
motion
The orbit of a planet revolving around a star is ______.
circular
linear
towards the focal point
elliptical
The square of its period of revolution around the sun is directly proportional to the ______ of the mean distance of a planet from the sun.
square
square root
cube
cube root
The gravitational force between two bodies is directly proportional to the product of the masses of those bodies and is ______ of the distance between them.
inversely proportional to the square.
directly proportional to the square.
inversely proportional to the cube.
inversely proportional to the square root.
The value of universal gravitational constant (G) in the SI unit is ______.
6.673 × 10−11 Nm2/kg2
6.673 × 1011 Nm/kg
9.673 × 10−11 Nm/kg
9.673 × 10−11 Nm2/kg2
The ______ force is much weaker than other forces in nature.
gravitational
electromagnetic
nuclear force
intermolecular
The value of gravitational acceleration (g) is ______.
highest at the poles.
highest at the equator.
same everywhere on the surface of the earth.
lowest at the poles.
The value of gravitational acceleration (g) is ______ at the equator.
9.78 m/s2
9.832 m/s2
9.8 m/s2
6.67 m/s2
The free fall of an object is possible only in ______.
air
vacuum
on the surface of earth.
None of these.
The weight of any object on the moon is nearly ______ of the weight of the earth.
1/6
1/8
1/2
2/6
A person weighs 60 N on earth. His weight on the moon will be ______.
360 N
60 N
6 N
10 N
SCERT Maharashtra solutions for साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड 1 Gravitation Right or Wrong sentence [Page 19]
Right or wrong sentence:
If the distance between two masses is doubled, the gravitational force between them becomes less than the previous force.
Right
Wrong
Right or wrong sentence:
The CGS unit of G is dyne.cm2/g2.
Right
Wrong
Right or wrong sentence:
The value of gravitational acceleration at the centre of earth is zero.
Right
Wrong
Right or wrong sentence:
The value of g is highest at the equator.
Right
Wrong
Right or wrong sentence.
The value of G varies from place to place.
Right
Wrong
Right or wrong sentence:
As we go above the earth's surface, value of g increases.
Right
Wrong
Right or wrong sentence.
The speed of release of an object does not depend on the mass of the object.
Right or wrong sentence.
Mass is a qualitative measure of the inertia of an object.
Right
Wrong
SCERT Maharashtra solutions for साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड 1 Gravitation Write scientific reasons [Pages 22 - 23]
Write scientific reasons.
The value of acceleration g is greater at the pole than at the equator.
Write scientific reasons.
The value of gravitational acceleration (g) decreases as we go above the Earth’s surface.
Write scientific reasons.
The value of gravitational acceleration (g) decreases as we go deep inside the earth.
Write scientific reasons.
When we drop a feather and a stone at the same time from a height the stone reach the earth faster than a feather.
Write scientific reasons.
The weight of an object varies on different planets.
Write scientific reasons.
The value of gravitational acceleration (g) is taken to be -g when studying the motion of an object thrown upwards in a straight line.
Write scientific reasons.
The value of g at the centre of the earth is zero.
SCERT Maharashtra solutions for साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड 1 Gravitation Solve the following Questions [Page 25]
Complete the following chart regarding the weight and mass of an object.
| Object | On Earth | On moon |
| Mass | X | ......... |
| Weight | ......... | Y |
Write the answer of the question with reference to laws of gravitation.
State the universal law of gravitation.
Define acceleration due to gravity.
Write the acceleration due to gravity value on the surface of Earth.
If a person weighs 750 N on Earth, what will be the weight of the person on the Moon?
(The mass of moon is `1/81` times the mass earth and its radius is `1/3.7` times that of earth.)
Mahendra and Virat are sitting at a distance of 1m from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them? (G = 6.67 × 10−11 Nm2/kg2)
Identify the mistake in the given diagram and draw it again.
The mass of planet ‘X’ is four times that of the earth, and its radius is double the radius of the earth. The escape velocity of a body from the earth is 11.2 × 103 m/s. Find the escape velocity of a body from the planet ‘X’.
SCERT Maharashtra solutions for साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड 1 Gravitation Distinguish between [Page 30]
Distinguish between:
Universal gravitational constant – Gravitational acceleration of earth.
SCERT Maharashtra solutions for साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड 1 Gravitation Write short notes [Page 31]
Write a short note.
Escape Velocity
Write a short note.
Free Fall
SCERT Maharashtra solutions for साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड 1 Gravitation Answer the Following [Page 33]
Observe the given figure and answer these following questions.
- What is the conclusion about the orbit of a planet?
- What is the relation between velocity of planet and distance from sun?
- ASB, CSD and ESF relation between areas explain.
OR
Write the Kepler’s laws.
State Newton’s universal law of gravitation. Express it with the mathematical form of force of gravitation?
An object takes 5 s to reach the ground from a height of 5 m on a planet. What is the value of g on the planet?
The radius of planet A is half the radius of planet B. If the mass of A is MA, what must be the mass of B so that the value of g on B is half that of its value on A?
The mass and weight of an object on earth are 5 kg and 49 N respectively. What will be their values on the moon? Assume that the acceleration due to gravity on the moon is 1/6th of that on the earth.
An object thrown vertically upwards reaches a height of 500 m. What was its initial velocity? How long will the object take to come back to the earth? Assume g = 10 m/s2.
A ball falls off a table and reaches the ground in 1 s. Assuming g = 10 m/s2, calculate its speed on reaching the ground and the height of the table.
The masses of the earth and moon are 6 × 1024 kg and 7.4 × 1022 kg, respectively. The distance between them is 3.8 × 105 km. Calculate the gravitational force of attraction between the two?
Use G = 6.7 × 10–11 N m2 kg–2
The mass of the earth is 6 × 1024 kg. The distance between the earth and the sun is 1.5 × 1011 m. If the gravitational force between the two is 3.5 × 1022 N, what is the mass of the sun? Use G = 6.7 × 10–11 N m2 kg–2
A tennis ball is thrown up and reaches a height of 4.05 m before coming down. What was its initial velocity? How much total time will it take to come down? Assume g = 10 m/s2?
SCERT Maharashtra solutions for साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड 1 Gravitation Answer the following questions [Page 48]
Read the given passage carefully and answer the questions.
| We know that the force of gravity due to the earth acts on each and every object. When we were holding the stone in our hand, the stone was experiencing this force, but it was balanced by a force that we were applying on it in the opposite direction. As a result, the stone remained at rest. Once we release the stone from our hands, the only force that acts on it is the gravitational force of the earth and the stone falls down under its influence. Whenever an object moves under the influence of the force of gravity alone, it is said to be falling freely. Thus the released stone is in a free fall. In free fall, the initial velocity of the object is zero and goes on increasing due to the acceleration due to the gravity of the earth. During free fall, the frictional force due to air opposes the motion of the object and a buoyant force also acts on the object. Thus, true free fall is possible only in a vacuum. |
- Complete the following statement by choosing the right option.
The stone held in the hand is stable because on it ......- two unbalanced forces are exerted.
- only the gravitational force of the earth is exerted.
- gravitational force of the earth is not exerted.
- two balanced forces are exerted.
- Why does free fall not happen on the earth?
- Why does the velocity of the object increase during the free fall?
- Which type of force exerts on the object during free fall?
- Why does free fall happen only in a vacuum?
Solutions for 1: Gravitation
SCERT Maharashtra solutions for साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड chapter 1 - Gravitation
Shaalaa.com has the Maharashtra State Board Mathematics साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड Maharashtra State Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. SCERT Maharashtra solutions for Mathematics साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड Maharashtra State Board 1 (Gravitation) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. SCERT Maharashtra textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.
Concepts covered in साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड chapter 1 Gravitation are Concept of Gravitation, Kepler’s Laws, Earth’s Gravitational Force, Escape Velocity, Uniform Circular Motion (UCM), Force and Motion, Earth’s Gravitational Acceleration, Mass and Weight, Gravitational Waves, Weightlessness in Space, Law of Orbit or Kepler's First Law, Law of Areas or Kepler's Second Law, Law of Periods or Kepler's Third Law, Centripetal Force, Newton's Universal Law of Gravitation, Free Fall, Gravitational Potential Energy.
Using SCERT Maharashtra साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड solutions Gravitation exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in SCERT Maharashtra Solutions are essential questions that can be asked in the final exam. Maximum Maharashtra State Board साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड students prefer SCERT Maharashtra Textbook Solutions to score more in exams.
Get the free view of Chapter 1, Gravitation साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड additional questions for Mathematics साइंस एण्ड टेक्नॉलोजी पार्ट १ [अंग्रेजी] कक्षा १० महाराष्ट्र राज्य बोर्ड Maharashtra State Board, and you can use Shaalaa.com to keep it handy for your exam preparation.
