Science (English Medium) कक्षा १२ - CBSE Question Bank Solutions for Chemistry

Give one chemical test to distinguish between the following pair of compounds.

Aniline and N-methylaniline

Account for the following:

pK_b of aniline is more than that of methylamine.

Account for the following:

Ethylamine is soluble in water, whereas aniline is not.

Account for the following:

Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.

How will you convert ethanoic acid into methanamine?

How will you convert hexanenitrile into 1-aminopentane?

How will you convert methanol to ethanoic acid?

How will you convert ethanamine into methanamine?

How will you convert ethanoic acid into propanoic acid?

How will you convert methanamine into ethanamine?

How will you convert nitromethane into dimethylamine?

How will you convert propanoic acid into ethanoic acid?

Accomplish the following conversion:

Benzoic acid to aniline

Accomplish the following conversion:

Aniline to 2, 4, 6-tribromofluorobenzene

Accomplish the following conversion:

Chlorobenzene to p-chloroaniline

Accomplish the following conversion:

Aniline to benzyl alcohol

An aromatic compound ‘A’ on treatment with aqueous ammonia and heating forms compound ‘B’ which on heating with Br₂ and KOH forms a compound ‘C’ of molecular formula C₆H₇N. Write the structures and IUPAC names of compounds A, B and C.

Complete the following reaction:

\[\ce{C6H5NH2 + H2SO4 (conc.)}\]

Complete the following reaction:

\[\ce{C6H5N2Cl + C2H5OH ->}\]

Complete the following reaction:

\[\ce{C6H5NH2 + Br2 (aq) ->}\]