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In Δ ABC and Δ PQR,
∠ ABC ≅ ∠ PQR, seg BD and
seg QS are angle bisector.
`If  (l(AD))/(l(PS)) = (l(DC))/(l(SR))`
Prove that : Δ ABC ∼ Δ PQR

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

Seg NQ is the bisector of ∠ N
of Δ MNP. If MN= 5, PN =7,
MQ = 2.5 then find QP.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

From the top of a light house, an abserver looking at a boat makes an angle of depression of 600. If the height of the lighthouse is 90 m then find how far is the boat from the lighthouse. (3 = 1.73)

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

In ΔABC, ray BD bisects ∠ABC.

If A – D – C, A – E – B and seg ED || side BC, then prove that:

`("AB")/("BC") = ("AE")/("EB")`

Proof : 

In ΔABC, ray BD bisects ∠ABC.

∴ `("AB")/("BC") = (......)/(......)`   ......(i) (By angle bisector theorem)

In ΔABC, seg DE || side BC

∴ `("AE")/("EB") = ("AD")/("DC")`   ....(ii) `square`

∴ `("AB")/square = square/("EB")`   [from (i) and (ii)]

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

In ΔABC, ∠ACB = 90°. seg CD ⊥ side AB and seg CE is angle bisector of ∠ACB.

Prove that: `(AD)/(BD) = (AE^2)/(BE^2)`.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

The ratio of the areas of two triangles with the common base is 4 : 3. Height of the larger triangle is 2 cm, then find the corresponding height of the smaller triangle.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Properties of Ratios of Areas of Two Triangles

In ∆ABC, B – D – C and BD = 7, BC = 20, then find the following ratio.

`(A(triangleABD))/(A(triangleABC))`

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Properties of Ratios of Areas of Two Triangles

In the given, seg BE ⊥ seg AB and seg BA ⊥ seg AD.

if BE = 6 and AD = 9 find `(A(Δ ABE))/(A(Δ BAD))`.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Properties of Ratios of Areas of Two Triangles

In the figure, ray YM is the bisector of ∠XYZ, where seg XY ≅ seg YZ, find the relation between XM and MZ. 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

In the above figure, line l || line m and line n is a transversal. Using the given information find the value of x. 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of Three Parallel Lines and Their Transversals

Draw seg AB = 6.8 cm and draw perpendicular bisector of it. 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

In the above figure, line AB || line CD || line EF, line l, and line m are its transversals. If  AC = 6, CE = 9. BD = 8, then complete the following activity to find DF. 

Activity :

`"AC"/"" = ""/"DF"`   (Property of three parallel lines and their transversal) 

∴ `6/9 = ""/"DF"`

∴ `"DF"  = "___"`

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of Three Parallel Lines and Their Transversals

In the following figure, ray PT is the bisector of QPR Find the value of x and perimeter of QPR.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

A roller of diameter 0.9 m and the length 1.8 m is used to press the ground. Find the area of the ground pressed by it in 500 revolutions.
`(pi=3.14)`

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Properties of Ratios of Areas of Two Triangles

Draw the circumcircle of ΔPMT in which PM = 5.6 cm, ∠P = 60°, ∠M = 70°.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

In ΔABC, B-D-C and BD = 7, BC = 20, then find the following ratio.

(i) `(A(ΔABD))/(A(ΔADC))`

(ii) `(A(ΔABD))/(A(ΔABC))`

(iii) `(A(ΔADC))/(A(ΔABC))`

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Properties of Ratios of Areas of Two Triangles

Prove that, The areas of two triangles with the same height are in proportion to their corresponding bases. To prove this theorem start as follows:

  1. Draw two triangles, give the names of all points, and show heights.
  2. Write 'Given' and 'To prove' from the figure drawn.
Appears in 1 question paper
Chapter: [1] Similarity
Concept: Properties of Ratios of Areas of Two Triangles

From the information given in the figure, determine whether MP is the bisector of ∠KMN.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

If ΔABC ∼ ΔDEF such that ∠A = 92° and ∠B = 40°, then ∠F = ?

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

If ΔABC ∼ ΔDEF, length of side AB is 9 cm and length of side DE is 12 cm, then find the ratio of their corresponding areas.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Properties of Ratios of Areas of Two Triangles
< prev  1581 to 1600 of 3865  next > 
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Maharashtra State Board SSC (English Medium) १० वीं कक्षा Important Questions
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Algebra Mathematics 1
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा English
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Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Hindi
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Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Marathi (Second Language) [मराठी (द्वितीय भाषा)]
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Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Sanskrit (Second Language) [संस्कृत (द्वितीय भाषा)]
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Sanskrit - Composite [संस्कृत - संयुक्त (द्वितीय भाषा)]
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